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a^2-37a+60=0
a = 1; b = -37; c = +60;
Δ = b2-4ac
Δ = -372-4·1·60
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1129}}{2*1}=\frac{37-\sqrt{1129}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1129}}{2*1}=\frac{37+\sqrt{1129}}{2} $
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